Second ODI / India won first in Rajkot, beating Australia by 36 runs; Kuldeep is the fastest Indian spinner to take 100 wickets
India scored the first 340, the Australian team was all out for 304 in 49.1 overs. Two batsmen missed the century in the match, first Dhawan out for 96 and Smith returned to the pavilion at 98 Three-match series 1-1, last match to be played in Bengaluru on January 19.
India defeated Australia by 36 runs in the second match of the three ODI series. With this victory, he brought the three-ODI series to 1-1. On Friday in Rajkot, Australia won the toss and decided to bowl first. India scored 340 for 6 wickets in 50 overs. The Australian team was reduced to 304 runs in 49.1 overs. This is Team India’s first win in three ODIs at this ground. Earlier in 2013, England and in 2015 South Africa were defeated.
The Indian spinner took two wickets in the match. He completed his 100 wickets in ODIs during this period. Kuldeep became the fastest Indian spinner to take 100 wickets. He achieved this feat in the 58th ODI. Next to them are Rashid Khan of Afghanistan (44 matches) and Saqlain Mushtaq of Pakistan (53 matches). Kuldeep equaled Imran Tahir. He left behind Harbhajan Singh (76 matches).
Most runs scored in a match in India without a century.
Kuldeep dismissed Smith and Carrie in the same over. Steve Smith missed out on a century. He was bowled by Kuldeep for 98 runs. Kuldeep dismissed Alex Carey (18) and took 100 wickets in ODIs. Ashton Turner (13) and Pat Cummins (0) were bowled by Shami. Smith shared a 96-run partnership for the third wicket with Marnesh Labushane. Labushane was out for 46 off Jadeja. Kuldeep took two or more wickets in an over for the 13th time.
